**********************ONLY NEED HELP WITH part C AND D*************** An electro

Question

**********************ONLY NEED HELP WITH part C AND D***************


An electron is placed at the origin of a coordinate system O, close to the surface of
the Earth as shown in the figure.
A second electron is placed on the y-axis at coordinate y so that the electrostatic force on
the electron at the origin balances the gravitational force.
a. Draw on the figure a force diagram for the electron at the origin.
b. Calculate the coordinate y of the second electron. Draw its position on the
figure.
The second electron is now replaced on the y-axis by a proton so that the electrostatic
force on the electron at the origin balances the gravitational force.
c. Calculate the coordinate y' of the proton. Draw its position on the figure.
The proton is now replaced on the y-axis by an electric dipole with an electric dipole
moment p=3.00x10^-30 C.m. The electric dipole moment vector p points along the
negative y-axis so that the electrostatic force on the electron at the origin balances the
gravitational force.
d. Calculate the coordinate y'' of the electric dipole. (Hint: The magnitude E of
the electric field E generated by an electric dipole along its axis is given by the equation:

E=(p/(2pi x E0 x y'')^3)

here are the answers but i want to learn how to do them

Answers
a. See figure
b. y =-5.08 m
c. y'= 5.08 m
d. y''=+- 9.88x10^-4 m

Explanation / Answer

Answers
a. See figure
b. y =-5.08 m
c. y'= 5.08 m
d. y''=+- 9.88x10^-4 m

b. Calculate the coordinate y of the second electron. Draw its position on the figure.

k q1 q2/y2 = m g

y2 = k q1 q2/m g = 9e9*1.6e-19*1.6e-19/(9.109e-31*9.8) = 25.8064

y = -5.08 m

c. Calculate the coordinate y' of the proton. Draw its position on the figure.
The proton is now replaced on the y-axis by an electric dipole with an electric dipole
moment p=3.00x10^-30 C.m. The electric dipole moment vector p points along the
negative y-axis so that the electrostatic force on the electron at the origin balances the
gravitational force.

k q1 q2/y2 = m g

y2 = k q1 q2/m g = 9e9*1.6e-19*1.6e-19/(9.109e-31*9.8) = 25.8064

y = 5.08 m

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