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Using Kirchhoff\'s rules, find the following. ( epsilon 1 = 71. 0 V, epsilon 2 =

ID: 1900609 • Letter: U

Question

Using Kirchhoff's rules, find the following. ( epsilon 1 = 71. 0 V, epsilon 2 = 61. 8 V, and epsilon 3 = 79. 6 V. ) the current in each resistor shown in the figure above You appear to have neglected the current passing through the 4. 00-k Ohm resistor. mA the potential difference between points c and f magnitude of potential difference Use the currents you calculated in part (a) of the problem to find the potential drop across the resistor and the potential difference that was requested. V point at higher potential

Explanation / Answer

a)

-2000 x + 71 - 61.8 + 3000 y = 0

-4000 z + 79.6 - 61.8 + 3000 y = 0

x + y + z = 0

i1 = 11/26000 = 0.423 mA

i2 = 181/65000 = 2.78 mA

i3 = 307/130000 = 2.36 mA

b)

61.8 + 3000 * 2.785e-3 = 70.2 V

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