X-ray photons of wavelength .02480nm are incident on a target and Compton-scatte

Question

X-ray photons of wavelength .02480nm are incident on a target and Compton-scattered photons are observed at 90 degrees. (a) What is the wavelength of the scattered photons? ***I came up with lambda prime = .027226nm*** (b) What is the momentum of the incident photons? Of the scattered photons? ***I was going to find the initial energy with the equation E=hf=hc/lambda and then find the momentum, but I am getting confused with the three different parts, the incident photons, scattered photons, and scattered electrons. I assume the energy of the incident photons is equal to the sum of the energy of the scattered photons and electrons.*** (c) What is the kinetic energy of the scattered electrons? (d) What is the momentum (magnitude and direction) of the scattered electrons?

Explanation / Answer

Use the equation below: E = (Nhc) / Lam E = energy in a mole of photons N = Avogadro’s number (photons per mole) h = Planck’s constant c= velocity of light (nm/sec) Lam= wavelength of light (nm) The units of energy calculated will depend on the units of Planck's constant used. If you want energy to be claculated in joules use h = 6.626 × 10^-34 J.s If you need the answer in eV, use h = 4.136 x 10^-15 eV.s This is described at the following link: http://www.tiem.utk.edu/~gross/bioed/webmodules/lightenergy.html N.B. There is one error on the page - the units for Planck's constant are cal.s (NOT cal/s) but other than it gives a simple

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