A Josephson junction (A = 8.9 x 10^-6 m^2) is made from two films of the same ma

Question

A Josephson junction (A = 8.9 x 10^-6 m^2) is made from two films of the same material, each with a concentration of 1.8 x 10^29 electrons/m^3). The insulator that separates these films has resistivity of 31.1 ohm-m, and has a potential energy barrier height of

1.25 x 10^-4 eV.

(a) If the maximum supercurrent supported by the junction is 2.22 mA, what is the thickness of the insulating layer between the superconductors?

Explanation / Answer

a) potential energy = 1.25 x 10^-4 eV ==> potential = /e = 1.25 * 10^-4 V R = /2.2m = 5.68*10^-2 ohm R= resistivity * thickness/area ==> thicness = 1.62 * 10^-8 m

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