The spectrometer consists of two regions as shown in the figure. In the first re
ID: 1896138 • Letter: T
Question
The spectrometer consists of two regions as shown in the figure. In the first region an electric field accelerates the ion and in the second the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured and then the m/q ratio can be found. After being accelerated to a speed of 1.51?105 m/s, the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 32.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q.
Find the ratio m/q for this particle.
The spectrometer consists of two regions as shown in the figure. In the first region an electric field accelerates the ion and in the second the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured and then the m/q ratio can be found. After being accelerated to a speed of 1.51?105 m/s, the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 32.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle.Explanation / Answer
Centripetal force = mv2/r
Lorentz force = qvb
qvb = mv2/r
=>m/q = br/v = 0.8*0.32/(1.51*105) = 1.695*10-6
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