DeeRed answer rating percentage100% [2 3 -1] [x] [ 1+k] [1 1 2 ] [y] = [ 6+k] [3

Question

DeeRed answer rating percentage100%

[2 3 -1] [x] [ 1+k]
[1 1 2 ] [y] = [ 6+k]
[3 -1 4] [z] [18+k]

Find its LU-decomposition and solve it by forward substitution followed by back substitution.

please.....Show me how you come up with the answer step by step.

Explanation / Answer

2x+3y-z=1+k x+y+2z=6+k 3x-y+z=18+k take k=0 ==> 2x+3y-z=1---1 x+y+2z=6---2 3x-y+z=18----3 x=4.68 y=-2.2 z=1.76 the solving can be done by below process 1+3 and 2*(2) and substracting both y will come similarly x and y can be calculated and http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut50_systhree.htm that link will be helpful depend on the k values the solution will be different

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