the answer is provided below the problem already Eva E. kicks a soccer ball, sta
ID: 1886112 • Letter: T
Question
the answer is provided below the problem already
Eva E. kicks a soccer ball, starting from midfield, with a velocity of magnitude v (m/s) and an angle X (degrees) relative to the +x1+yl-xl-y-axis. Owing tothe peculiarities of astro-turf, assuming the soccer ball has an acceleration of a making an angle of Y (degrees) relative to the +xl+yl-xl-y-axis (m/s2), determine how far the ball moves in the x- and y- directions, respectively, after a time t seconds, the total displacement from it's starting point (m) (aside: problem is only approximate, since velocity is changing with time!) Now insert values: 2) Assign: lv-20 m/s, 0,+53.1°, relative to +y 3) Solve problem for t-1.8 seconds +60° -x lal 2 m/s2, 0 +60°, relative to +x 28 x: x,-0-16*1.8 + 0.5+1+1.8*1.8-27.18 m Y-12*1.80.5*1.732*1.8*1.8-24.41 m Total displacementsqrt(24.412 (-27.18)2)-36.53Explanation / Answer
from the figure,
x-component of velocity,
vx = -20*sin(53.1) = -16 m/s
y-component of velocity,
vy = 20*cos(53.1) = 12 m/s
x-component of acceleration,
ax = 2*cos(60) = 1 m/s^2
y-component of acceleration,
ay = 2*sin(60) = 1.732 m/s^2
time taken, t = 1.8 s
we know, displacement in x-direction,
delta_x = vx*t + (1/2)*ax*t^2
= (-16)*1.8 + (1/2)*1*1.8^2
= -27.18 m
we know, displacement in y-direction,
delta_y = vy*t + (1/2)*ay*t^2
= 12*1.8 + (1/2)*1.732*1.8^2
= 24.4 m
total displacement = sqrt(delta_x^2 + delta_y^2)
= sqrt(27.18^2 + 24.4^2)
= 36.5 m <<<<<<<<---------------Answer
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