a 2965 Help 1 Contact Us1 Log.Out OSCutnell, Physics, 11e GENERAL PHYSICS (PHYS

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a 2965 Help 1 Contact Us1 Log.Out OSCutnell, Physics, 11e GENERAL PHYSICS (PHYS 2001/2002) ssignment Chapter 02, Problem 36 GO | acceleration has a magnitude of .42 m/s2. (a) How much tme-s before the players collide? (b) At the instant they collide, how far has the Two soccer players start from rest, 39 m apart. They run directly toward each other, both s players accelerating. The first player's acceleration has a magnitude of 0.60 m/s?. The second player's player run, (a) Number Units (b) Number Units Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER MapleNet Version 4.24.9.3

Explanation / Answer

let the two players accelerate for time "t"

for first player :

vi = initial velocity = 0 m/s

a = acceleration = 0.60 m/s2

d = distance travelled in time "t"

using the equation

d = vi t + (0.5) a t2

d = (0) t + (0.5) a t2

d = (0.5) (0.60) t2 eq-1

for second player :

v'i = initial velocity = 0 m/s

a' = acceleration = 0.42 m/s2

d' = distance travelled in time "t"

using the equation

d' = v'i t + (0.5) a' t2

d' = (0) t + (0.5) a' t2

d' = (0.5) (0.42) t2 eq-2

Given that

d' + d = initial distance between the players = 39 m

(0.5) (0.42) t2 + (0.5) (0.60) t2 = 39

t = 8.74 sec

b)

using eq-1

d = (0.5) (0.60) t2

d = (0.5) (0.60) (8.74)2

d = 22.92 m

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