River A and River B have the flow rates of 0.005 m3/sec and 0.003 m3/sec, respec

Question

River A and River B have the flow rates of 0.005 m3/sec and 0.003 m3/sec, respectively. River A and River B carry nitrogen concentrations of 15 mg/L. and 20 mg/L, respectively, Both rivers merged in a junction C. Determine the flow rate and resulting nitrogen concentration at C Q. Flow rate: 4L/sec, Nitrogen concertation: 16.88 mg/L Flow rate: 8/sec, Nitrogen concertation: 10.2 mg/L Flow rate: 4L/sec, Nitrogen concertation: 10.2 mg/L Flow rate: 8L/sec, Nitrogen concertation: 16.88 mg/L QUESTION 3 Calculate the missing outlet concentration. 3 L/sec, 500 mg/L 5 L/sec, 200 mg/L 8 L/sec, concentration= ?

Explanation / Answer

answer no 5: D...Consider flow be 1 so, resultant concentration will be 6*1+0*1/1+1=3mg/L...

answer no 7 : 1.5*6+0*10/10+1.5=0.78mg/L....So the answer is 0.78mg/L

answer no 4: Flow rate 3L/sec and concentration is 138.34mg/L

answer no 2: Flow rate is adding all that is 5+3=8L/sec and concentration is above process is 16.88mg/L

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.