4. You have two heterozygous solid black cats. Complete a punnett square illustr

Question

4. You have two heterozygous solid black cats. Complete a punnett square illustrating this cross. What fraction of the offspring will have solid orange coats? 5. You have a heterozygous solid black male and a homozygous striped orange female. Complete a punnett square of this cross. How many of the offspring will look like the father? 6. You have a homozygous solid black male and a homozygous striped orange female. Complete a punnett square of thi cross. How many of the offspring will look like the mother?

Explanation / Answer

Please find the answers below:

According to the information, it is suggestive that solid black phenotype is dominant over solid orange phenotype. Thus, homozygous dominant would be balck, heterozygotes will be striped whereas homozygous recessive would be solid orange. Thus the answers can be found as below:

Answer 1: The cross is made between heterozygous black cats i.e. Bb and Bb. The Punnett square can be found as below:

Thus, phenotype: Black : Orange :: 3:1

Thus, the fraction of solid orange 1/4 or 25%.

Answer 2: The cross is made between black male i.e. BB and a striped female i.e. Bb. The Punnett square can be found as below:

Thus, phenotype: Black : striped :: 1:1

Thus, 50% of the offsprings would look like the father.

Answer 3: The cross is made between black male (BB) and striped female (Bb). Thus the Punnett square can be found as below:

Thus, phenotypic ratio= Black : striped organge :: 1:1

Thus, 50% of the offsprings would look like the mother.

B b B BB Bb b Bb bb

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