Determine the E Sold (magnitude) caused by the heart\'s dipole at a distance of
ID: 1883838 • Letter: D
Question
Determine the E Sold (magnitude) caused by the heart's dipole at a distance of 7.6 cm directly above the hearts positive charge. All charges are located in body tissue of dielectric constant 7.0 Express your answer to two significant figures and include the appropriate units. Constants The heart has a dipole charge distribution with a charge of +1.0x10 7 C that is 5.2 cm above a charge of -1.0x10-7 C B-1 Value Units Submit Part B Determine the E feld (direction) caused by the hearts dipole at a distance of 7 6 cm directly above the hearfs posilive charge 0 downward O upwardExplanation / Answer
Electric field due to - q, E1 = kq/er^2
Electric field due to +q = E2 = kq/es^2
E = E2 - E1 = kq/e [(1/0.076^2) - (1/(0.076 + 0.052)^2)]
E = 1.44 x 10^4 N/C
B)
Direction of field is directed upwards.
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