PLEASE HELP WITH B) HOW LONG IS THE PROJECTILE IN THE AIR FOR? Written 3.pdf XC

Question

PLEASE HELP WITH B) HOW LONG IS THE PROJECTILE IN THE AIR FOR?

Written 3.pdf XC Chegg Study | Guided Solut+ K file:///C/Users/b 1. A projectile is launched towards a target on a hill at an elevation of 9.5 m, as shown in Fig. 1 below. The projectile reaches a maximum height of 17 m when it is directly above the base of the hill. The base of the hill is 26 m from the location that the projectile is launched. highest point 17 m 9.5 m 26 m Figure 1: The path of the projectile. a) What is the magnitude and direction angle of the initial velocity of the projectile? b) How long is the projectile in the air for? There are couple different ways to approach these problems. You do not need to use the quadratic formula to solve either part of this problem, but you can if you would like to 3:37 PM O Type here to search t n o ENG 2018-09-25 3

Explanation / Answer

time of fligth Tf = 2 u sin theta/g

Hamx = u^2 sin^2 theta/2g

u^2 sin^2 theta = 2 g Hmax

u^2 sin^2 theta = 2* 9.81* 17

u sin theta = 18.26

so

Tf = 2 * 18.26/9.81

Tf = 3.72 sec

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