(8%) Problem 2: A skydiver plunges d,-450 meters in t,-7.9 s before releasing hi
ID: 1882619 • Letter: #
Question
(8%) Problem 2: A skydiver plunges d,-450 meters in t,-7.9 s before releasing his parachute. After the chute opens, he plunges an additional d2-845 meters in t2-139 s. See the figure Otheexpertta.co 25% Part (a) Enter an expression for the skydiver's average speed, vi , during the period before releasing the chute in terms of the given quantities. Grade Summary Deductions Potential Late Work % 50 Late Potential 50 Submissions Attempts remaining % per attempt) detailed view 0 END Submit Hint I give up! Hints: 1 % deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 25% Part (b) Enter an expression for the skydiver's average speed, v2 during the period after releasing the chute in terms of the given quantities 25% Part (c) Enter an expression for the skydiver's average speed during the entire fall, va in terms of the given quantities 25% Part (d) Calculate the skydiver's average speed during the entire fall, v, in meters per secondExplanation / Answer
Average velocity = total distance/ toatal time
(A) v1 = d1/t1 = 450/7.9 = 56.96m/s
(B) v2 = d2/t2 = 845/139 = 6.08m/s
(C) va = (d1+d2)/(t1+t2)
= 1295/146.9 = 8.82m/s
(D) quantities are already in term of meter per second so ans is 8.82 mater per second
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