1. Two charges, one is 3 nC and another one is 21 nC are separated by 1 m distan
ID: 1881857 • Letter: 1
Question
1. Two charges, one is 3 nC and another one is 21 nC are separated by 1 m distance. Calculate distance from the smaller charge where electric field will be zero.2. How many electrons have to be added to 1 gram metal sphere such that another +1C charge located 23 mm above the sphere will be able to hold that in the air?[Assume g=10m/s^2].
3. Two point charges, q= +16 nC and q= -6 nC, are located on the x-axis at x= 0 and x=9 m. What is the distance of ZERO electric field from the positive charge?
1. Two charges, one is 3 nC and another one is 21 nC are separated by 1 m distance. Calculate distance from the smaller charge where electric field will be zero.
2. How many electrons have to be added to 1 gram metal sphere such that another +1C charge located 23 mm above the sphere will be able to hold that in the air?[Assume g=10m/s^2].
3. Two point charges, q= +16 nC and q= -6 nC, are located on the x-axis at x= 0 and x=9 m. What is the distance of ZERO electric field from the positive charge?
1. Two charges, one is 3 nC and another one is 21 nC are separated by 1 m distance. Calculate distance from the smaller charge where electric field will be zero.
2. How many electrons have to be added to 1 gram metal sphere such that another +1C charge located 23 mm above the sphere will be able to hold that in the air?[Assume g=10m/s^2].
3. Two point charges, q= +16 nC and q= -6 nC, are located on the x-axis at x= 0 and x=9 m. What is the distance of ZERO electric field from the positive charge?
Explanation / Answer
1.)
E = kq/r^2
If field is zero
E1 = E2
kq1/r1^2 = kq2/r2^2
3/x^2 = 21 / (1-x)^2
x = 0.274m
2.)
Fg = Fc
mg = Eq
10^-3 x 9.8 = k q/ (0.023)^2 x1
q = 10^-3 x 9.8 x 0.023^2 / 9 x 10^9 = 5.76 x 10^-16 C
but q = ne
n = q/e = 5.76 x 10^-16 / 1.6 x 10^-19
= 3600
3. ) same as 1
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