Two cars collide at an intersection. Car A , with a mass of 1900 kg , is going f

Question

Two cars collide at an intersection. Car A , with a mass of 1900 kg , is going from west to east, while car B , of mass 1300 kg , is going from north to south at 14.0 m/s . As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 65.0 south of east from the point of impact. Question in picture. cs.com/myct/itemView?offset-next&assignmentProblemID-99981628 Part A How fast were the enmeshed cars moving just after the collision? m/s Submit Part B How fast was car A going just before the collision? n/s Submit Request Answer 0o

Explanation / Answer

Solution:-

Collision :- A collision is an event in which two or more bodies exert forces on each other for a relatively short time. Although the most common colloquial use of collision refers to incident in which two or more object collide with great force. The scientific use of the word collision implies nothing about the magnitude of the force.

Ther are two types of collsion

For car A ,

Given – mass = 1900kg

Using the formula for momentum ,

Momentum = mass * velocity

P = m*u

Where , p-momentum

               m-mass

               u – velocity

P = 1900*u Ns (1) ( use u as velocity so there is no confusion later on.)

For car B

Given – mass = 1300kg

               Velocity = 14.0m/s

Using the formula for momentum ,

Momentum = mass * velocity

P = m*v

Where , p-momentum

               m-mass

               v – velocity

P = 1300*14.0m/s

P= 18,200Ns

For Enmeshed cars

Find total mass,

M= 1300kg+1900kg

M = 3200 kg

So, therefore momentum is given by,

P = mv

P = 3200 * v Ns

Rsolved vectors

= 65.00

Adjecent (A) = 1900*u

Opposite (O) = 18200

Hypotenuse (H)= 3200*v

Part A ) Calculate how were the enmeshed cars moving just after the collision

sin( ) = Opposite(O) / Hypotenuse(H)

sin(65) = 18200/3200*v

V = 18200 / 3200*sin(650)

V = 6.2 m/s

The enmeshed cars are moving at 6.2 m/s

Part B) Calculate how fast was cars A moving just abefore the collision

Tan () = Opposite(O) / Adjecnet (A)

tan(650) = 18200/(1900*v)

V = 18200 / 1900*tan(650)

V = 4.4 m/s

The car A is moving at 4.4 m/s ,just before the collision.

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