Two cars collide at an intersection. Car A , with a mass of 1900 kg , is going f
ID: 1774953 • Letter: T
Question
Two cars collide at an intersection. Car A, with a mass of 1900 kg , is going from west to east, while car B , of mass 1500 kg , is going from north to south at 15 m/s . As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 65 south of east from the point of impact.
Part A
How fast were the enmeshed cars moving just after the collision?
Express your answer using two significant figures.
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Part B
How fast was car A going just before the collision?
Express your answer using two significant figures.
Two cars collide at an intersection. Car A, with a mass of 1900 kg , is going from west to east, while car B , of mass 1500 kg , is going from north to south at 15 m/s . As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 65 south of east from the point of impact.
Part A
How fast were the enmeshed cars moving just after the collision?
Express your answer using two significant figures.
v = m/sSubmitMy AnswersGive Up
Part B
How fast was car A going just before the collision?
Express your answer using two significant figures.
vA = m/sExplanation / Answer
Momentum is conserved before and after the collision in both x and y direction.
so, for x direction:
1900u + 1500(0) = (1900 + 1500)Vcos65
=> u = 0.7563V
and for y direction:
1900(0) - 1500(15) = - (1900 + 1500)Vsin65
=> V = 7.302 m/s
this is how fast the enmeshed cars were moving after collision.
now, u = 0.7563V
therefore, u = 0.7563 x 7.302 = 5.520 m/s
this is how fast car A was going before the collision.
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