10) Consider the system shown in the figure (Figure 1). Block A weighs 40.6 N an

Question

10) Consider the system shown in the figure (Figure 1). Block A weighs 40.6 N and block B weighs 24.8 N . Once block B is set into downward motion, it descends at a constant speed.

Constents Part A Consider the system shown in the figure (Figure 1). Block A weighs 40.6 N and block B weighs 24.8 N. Once block B is set into downward motion, it descends at a constant speed. Calculate the coefficient of kinetic friction between block A and the tabletop. - 10.54 Submit Figure 1 of 1 X Incorrect; Try Again; 5 attempts remaining Part B A cat, also of weight 40.6 N , falls asleep on top of block A. tf block B is now set into downward motion, what is its acceleration magnitude? m/s

Explanation / Answer

Part A -

As the block B moves at constant speed,

Therefore,

Wb = ukWa

where Wb and Wa are the weights

uk = Wb / Wa

uk = 24.8 / 40.6

uk = 0.6108

Part B -

with cat sitting on block A,

net force, F = 24.8 - 0.6108*81.2 (2 * 40.6 = 81.2)

F = -24.796 N

Now,

a = F/m

a = -24.796 / 80.2 / 9.8 + 24.8/9.8

a = -2.314 m/s2

magnitude, a = 2.314 m/s2

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