Two forces are applied to a car in an effort to move it, as shown in the figure

Question

Two forces are applied to a car in an effort to move it, as shown in the figure below. (Let F1-400 N and F2 355 N. Assume up and to the right are in the positive directions.) 10° 80° (a) What is the resultant vector of these two forces? magnitude 7.1e2 direction 11.24x Your response differs from the correct answer by more than 10%. Double check your calculations. to the right of the forward direction (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. 0.237m/s2

Explanation / Answer

a) for the resultant of two vector

magnitude = sqrt(400^2 + 355^2 + 2* 400 * 355 * cos(40 degree))

magnitude = 709.6 N

the magnitude of the resultant is 709.6 N

direction of F1 = atan(355 * sin(40)/(400 + 355 * cos(40))) - 10

direction of F1 = 8.75 degree

direction of F1 is 8.750to the right

b)acceleration = 709.6/3000

acceleration = 0.23 m/s^2

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