My Notes A charge 1 1.82 HC is at a distance d 1.33 m from a second charge q25.9

Question

My Notes A charge 1 1.82 HC is at a distance d 1.33 m from a second charge q25.97 HC 42 (a) Find the electric potential at a point A between the two charges that is d/2 from q1. Note that the location A in the diagram above is not to scale. (b) Find a point between the two charges on the horizontal line where the electric potential is zero. (Enter your answer as measured from q1) dditional Materials La Reading Tutorial Submit Assignment Save Assignment Progress Home My Assignments Extension Request

Explanation / Answer

Part A

electric potential is a scalar quantity, which is given by:

V = kQ/R

Now net electric potential will be

Vnet = V1 + V2

Vnet = kQ1/R1 + kQ2/R2

Q1 = 1.82 uC, & Q2 = -5.97 uC

R1 = R2 = d/2 = 1.33/2 = 0.665 m

So,

Vnet = 9*10^9*1.82*10^-6/0.665 - 9*10^9*5.97*10^-6/0.665

Vnet = -56165.4 V

Part B.

Electric potential is a scalar quantity, which is given by:

V = kQ/R

Suppose at distance 'x' from q1, betwwen both charges net electric potential is zero, then

Vnet = V1 + V2 = 0

V1 = -V2

kQ1/R1 = -kQ2/R2

Q1/R1 = -Q2/R2

R1 = x, & R2 = d - x = 1.33 - x

So

1.82/x = -(-5.97)/(1.33 - x)

1.82*(1.33 - x) = 5.97*x

x = 1.82*1.33/(5.97 + 1.82)

x = 0.311 m

Electric potential is zero at x = 0.311 m

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