My Institution My Courses Community Content O Save & End Certify Lesson:74 Addit

Question

My Institution My Courses Community Content O Save & End Certify Lesson:74 Addition and Multiplication Ru.. ARIELLE NEWBY Question 10 of 12, Step 1 of 1 9/12 Correct The following table shows the breakdown of opinions for both faculty and students in a recent survey about the new restructuring of the campus to include an Honors College. Find the probability that a randomly selected person is either neutral or opposed to the restructuring, Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth. Favor 19 67 86 Oppose 15 Neutral Total Faculty Students Total 218 Copy Data Keypad to enter your answer

Explanation / Answer

For the given table values,

we have to find the probability that a randomly selected person is either neutral or opposed to restructring.

Pr(natural or Opposed to restructuring) = Total nube of people who are neutral or opposed to restructiing/ Total number of people in the sample

= (88 + 44)/ 218 = 0.605505

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.