1. 1/2 points | Previous Answers SerPSET9 23 P002. My Notes Ask Your Teacher (a)

Question

1. 1/2 points | Previous Answers SerPSET9 23 P002. My Notes Ask Your Teacher (a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 8.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol. 20.973.10 (b) Imagine adding electrons to the pin until the negative charge has the very large value 3.00 mC. How many electrons are added for every 109 electrons already present? 0.6710X Note that 109 is one billion. It might help to rewrite your answer from part (a) as the number of billions of electrons. Need Help? Watch

Explanation / Answer

as you got part A right ,i am answering only part B

b)

n=Q/e =(3*10-3)/(1.6*10-19)

n=1.875*1016 electron

Therefore

N =[(1.875*1016)/(2.0973*1024)]*109

N=8.94

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