14. (1ptj The diagram below shows time exposure images of two balls travelling a
ID: 1880472 • Letter: 1
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14. (1ptj The diagram below shows time exposure images of two balls travelling along the x axis. The time of each image is indicated next to it Ball A Ball B .. . -... Answer each of the questions below by choosing from the following options (e.g. if the answer to the first question is ball A, to the second, ball B', and to the rest, cannot tell, enter ABCCCC) A) ball A, B) ball B, C cannot tell, D) both, N) neither. i. Which ball has a greater average speed between times 3 and 4? ii. For which ball does the acceleration vector point to the right at time 4? ii For which ball is the acceleration constant throughout its motion? iv. For which ball does the average acceleration between times 2 and 3 equal zero v. For which ball is its average speed between times 1 and 2 different from its average speed between times 3 and 4 vi. For which ball does the acceleration vector point to the left at time 1? Submia All Aewors Last Answer: ABAABN Incsrrect, tries 7/1 Dalhousle Physics GIGABYTEExplanation / Answer
1.
Average Speed = Distance Traveled/Time taken
from the graph we can see that distance traveled for Ball A > Ball B for the same time period from 3 to 4.
Now since Speed is directly proportional to the distance travled when time is same, So Avg Speed of Ball A will be greater than Avg Speed of Ball B.
Correct option is A.
2.
Since for ball A distance travled for each period is equal, which means it's velocity is constant, So it's acceleration will be zero.
For ball B distance traveled by ball in each time period is reducing which means velocity is reducing, So there is de-acceleration. Since velocity is towards right and reducing, which means it's acceleration will be towards left.
Correct option is N.
3.
from part 2, acceleration is constant for ball A.
Acceleration of Ball B is cannot be deduced without data for each time period, So
Correct option is C.
4.
Average acceleration = change in speed/time taken
Since change in speed is zero for ball A during each period, So Avg acceleration will be zero for ball A.
Correct option is A.
5.
we have already found that Avg speed of ball A is constant.
For ball B, distance traveled between 1 and 2 is higher than distance traveled between time 3 and 4, So
Avg speed will be higher for time between 1 and 2, than time between 3 and 4
So Correct option is B.
6.
from part 2.
acceleration of Ball A is zero.
For ball B distance traveled by ball in each time period is reducing which means velocity is reducing, So there is de-acceleration. Since velocity is towards right and reducing, which means it's acceleration will be towards left.
Correct option is B.
Correct Sequence will be ANCABB.
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