Three push against one another. Their masses are (from left are observed to acce

Question

Three push against one another. Their masses are (from left are observed to accelerate to the left at a rate of 0.5 m/s?. If the man on the left is pushing on the left box with a constant force 100N in the direction shown, boxes are sitting on a frictionless floor as shown. They are touching one another and can to right) 10kg, 6kg, and 8kg. The boxes a) What must be the constant force exerted by the man on the right? b) What are the forces with which the boxes push against each other? 10kg 6kg 8kg

Explanation / Answer

here,

m1 = 10 kg , m2 = 6 kg

m3 = 8 kg

force from the left , Fl = 100 N

accelration , a = 0.5 m/s^2

a)

let the constant force exerted by the man on the right be Fr

accelration = net force/effective mass

a = ( Fr - Fl)/(m1 + m2 +m3)

0.5 * ( 10 + 6 + 8) = ( Fr - 100)

Fr = 112 N

b)

the force between 8 kg and 6 kg be f1

Fr - F1 = m3 * a

112 - F1 = 8 * 0.5

F1 = 108 N

the force between 10 kg and 6 kg be f2

F1 - F2 = m2 * a

108 - F2 = 6 * 0.5

F2 = 105 N

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