A capacitor consists of two closely spaced metal conductors of large area, separ

Question

A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electrical capacity of 3200.0 F and is charged to a potential difference of 81.0 V. Calculate the amount of energy stored in the capacitor.

Calculate the charge on this capacitor when the electrical energy stored in the capacitor is 10.50 J.

If the two plates of the capacitor have their separation increased by a factor of 5 while the charge on the plates remains constant, by what factor is the energy stored in the capacitor increased?

Explanation / Answer

Solution,

Given

Potential difference, V = 81 V

A) Energy, E = 0.5 CV^2 = 0.5 x 3200 x10^-6 x 81^2 = 10.5 J

B) Energy, E = 0.5 Q^2/C

Q = sqrt( 2 E C ) = sqrt (2 x 10.5 x 3200 x10^-6) = 0.259 C

C) Capacitance decreases by a factor of 5, so the energy increases by a factor of 5

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