A capacitor (5.10 F ) is connected in a parallel arrangement with a second capac

Question

A capacitor (5.10 F ) is connected in a parallel arrangement with a second capacitor (1.90 F ) and in series with a 12-V battery.

The battery is then removed, leaving the two capacitors isolated.
If the smaller capacitor's capacitance is now doubled, by how much does the charge on the larger capacitor change?

By how much does the charge on the smaller capacitor change?

By how much does the voltage across the larger capacitor change?

By how much does the voltage across the smaller capacitor change?

Explanation / Answer

a) as voltage is same on both capacitor..

Qnew = 2CV

=> Qnew = 2Qold

b)

voltage don't changed

c) voltage don't change

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.