A rescue plane wants to drop supplies to isolated mountain climbers on a rocky r

Question

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below Part A If the plane is traveling horizontally with a speed of 268 km/h (74.4 m/s ), how far in advance of the recipients (horizontal distance) must the goods be dropped (see the figure (Figure 1) (a) )? x = nothing    m   SubmitPrevious AnswersRequest Answer Incorrect; Try Again Part B Suppose, instead, that the plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position

Explanation / Answer

Here ,

h = 235 m

part A) horizontal speed , u = 74.4 m/s

Now , let the time taken is t

t = sqrt(2h/g)

t = sqrt(2 * 235/9.8)

t = 6.93 s

for the distance x

x = 74.4 * 6.93

x = 515 m

part B)

let the vertical velocity needed is uy

Now, for the time of flight

t = 425/74.4

t = 5.71 s

Now, for the supplies to reach the ridge

y = uy * t + 0.50 at^2

- 235 = uy * 5.71 - 0.50 * 9.8 * 5.71^2

solving for uy

uy = -13.2 m/s

hence , the initial velocity given should be 13.2 m/s in downwards direction

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