r word-Chapte 4. Us XV a iz Solutions Set 1.pdf xTo Calculu s Early Transce -×Va
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r word-Chapte 4. Us XV a iz Solutions Set 1.pdf xTo Calculu s Early Transce -×Va The Expert TA Human--99999 .> C https://usm42sc.theexpertta.com/Common/TakeTutorialAssignment.aspx (1196) Problem 6: A rocket accelerates upward from rest, due to the first stage, with a constant acceleration of a -77 ms for t-58 s. The first stage then detaches and the second stage fires, providing a constant acceleration of a2 38 m st for the time interval 2-58 s. acceleration two Assignment Statu:s Click here for detailed view Problem Status ©theexpertta.com 1 Partial 2 Completed 3 Completed 4Completed 5 Partial 6 Partial 7 Completed S Completed 9 Completed 33% Part (a) Enter an expression for the rocket's speed, vi, at time ti n terms of the variables provided. v-a Correct! 33% Part (b) Enter an expression for the rocket's speed, v2, at the end of the second period of acceleration in terms of the variables provided in the problem statement. Grade Summary 296 98% Potential 7 89 HOME Submissions Attempts remaining: 2 (09% per attempt) detailed view a1 09% 09% 09% BACKSPACE I DELI CLEAR Submit I give up! avascriptETAProbNav.clickPart(5, 2) O Type here to search 3:05 PM 9/13/2018Explanation / Answer
Initial velocity for stage 2 will be
u2 = v1 = a1*t1
acceleration = a2
time period = t2
final velocity is suppose v2, then
v2 = u2 + a2*t2
v2 = a1*t1 + a2*t2
Since we need v2 in terms of variable provided, So we need not to calculate u2.
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