6. 0/5 points | Previous Answers SerPSE8 26.P.014.wi. My Notes Two capacitors (C

Question

6. 0/5 points | Previous Answers SerPSE8 26.P.014.wi. My Notes Two capacitors (C1-2.00 F and C2-13.0 F) are now connected in series and to a 9.00-V battery. (a) Find the equivalent capacitance of the combination. 5.33 Connecting capacitors in series effectively combines the distance between plates. Can the equivalent capacitance be greater than either plate by itself? F (b) Find the potential difference across each capacito () Find the charge on each capacitor. Q1= uC Need Help?ReadItWatch It Talk to a Tutor

Explanation / Answer

when Capacitors are connected in Series,

1/Ceq = 1/C1 + 1/C2

Ceq = C1*C2/(C1 + C2)

Ceq = 2*13/(2 + 13)

Ceq = 1.73 uF

Now using equation

Qeq = Ceq*V

Qeq = 1.73*10^-6*9.00 = 15.6*10^-6 C

Since Capacitors are connected in Series, So charge on each capacitors will be same

Charge on 2 uF capacitor = 15.6 uC

Charge on 13 uF capacitor = 15.6 uC

Now Voltage will be

Voltage = Q/C

Voltage on 2 uF = 15.6*10^-6/(2*10^-6) = 7.8 V

Voltage on 13 uF = 15.6*10^-6/(13*10^-6) = 1.2 V

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