A point charge q-+5 uC is at the center of a sphere of radius 0.4 m. (a) Find th

Question

A point charge q-+5 uC is at the center of a sphere of radius 0.4 m. (a) Find the surface area of the sphere. m2 (b) Find the magnitude of the electric field at points on the surface of the sphere. N/C (c) What is the flux of the electric field due to the point charge through the surface of the sphere? N m2/c (d) Would your answer to part (c) change if the point charge were moved so that it was inside the sphere but not at its center? yes no not enough information to decide (e) What is the net flux through a cube of side 2 m that encloses the sphere? N m2/c

Explanation / Answer

(A) A = 4 pi r^2 = 4 x pi x 0.4^2

A = 2.01 m^2

(B) E = k Q / r^2 = (9 x 10^9)(5 x 10^-6)/0.4^2

E = 281250 N/C

E = 2.81 x 10^5 N/C

(C) flux = E.A = 5.65 x 10^5 Nm^2/C

(d) from Gauss law,

flux through closed surface = Q_enclosed / e0

charge is moved but still inside and magnitude is same

so flux will not change.

Ans: no

(e) flux = Q_en / e0

= (5 x 10^-6)/(8.854 x 10^-12)

= 5.65 x 10^5 N m^2 /C

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