A particle moves in a circular motion, with the relation between acceleration, v
ID: 1877386 • Letter: A
Question
A particle moves in a circular motion, with the relation between acceleration, velocity and radian in: a=k.r^n.v^m, where k is a constanta that doesn’t have a dimension.The question: can k be another constanta other than 1?
(I doubt my answer as I know, the acceleration in circular motion is a=v^2/r, from the equation above i only see the possibility of k is and only 1, please help me!) A particle moves in a circular motion, with the relation between acceleration, velocity and radian in: a=k.r^n.v^m, where k is a constanta that doesn’t have a dimension.
The question: can k be another constanta other than 1?
(I doubt my answer as I know, the acceleration in circular motion is a=v^2/r, from the equation above i only see the possibility of k is and only 1, please help me!)
The question: can k be another constanta other than 1?
(I doubt my answer as I know, the acceleration in circular motion is a=v^2/r, from the equation above i only see the possibility of k is and only 1, please help me!)
Explanation / Answer
The acceleration is equal to the square of the velocity, divided by the radius of the circular path. ac = v2/r so, if you take this equation a=k.r^n.v^m , k must have value equal to 1 otherwise the relation will be incorrect.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.