PHYSICS 207 Test I KM September 8, 2017 Do all five problems. Show all steps and

Question

PHYSICS 207 Test I KM September 8, 2017 Do all five problems. Show all steps and carefully explain your solutions. All drawings must be carefully drawn and labeled and, when necessary, include arrows to indicate directions. Yours answers will be judged on clarity. You are being judged on your ability to understand and translate word problems therefore refrain from asking me to interpret statements. I will provide you with any constant or conversion unit when you ask for it. Solve each problem on a new page. YOUR BONUS POINTS wILL BE SET TO ZERO SHOULD YOU FAIL TO SOLVE EACH PROBLEM ON A NEW PAGE 1. Explain how a negatively charged object can be used to leave another metallic object with a net positive charge. Discuss the motion of charges during the process. Use drawings to support the steps involved in the process 2. Two point charges are located as follows: charge 0 -180C is at (3.00,2.00) m and charge 15.0 uC is at (4.00,-3.00) m. (a) Determine the magnitude and polar angle of the electric field at (4.00,0.00) m (b) A negative charge, Q-. 6.00 C is placed at the location (4.00, 0.00) m in problem 2(a), what is the magnitude and polar angle of the electric force on this charge? 3. How many atoms are there in 5.60 kg of plutonium given that its atomie mass is 244? a. How many electrons are there in the 5.60 kg of plutonium given that each plutonium atom has 94 electrons? b. Ifthe pktonium attains a charge of +30 C, how many electrons were removed? c. What fraction of the plutonium's electrons has been removed? 4. A proton is placed in a region where the electric field is 5.75 x 10-12N/C a. What is the electric force experienced by the proton? b. What is the acceleration of the proton? c. If the proton starts from rest, what is its speed after 6.00s? d. How far does the proton move in 6.00s? e. What is the kinetic energy of the proton at this time? Charge of proton 1.6 x 10-C ; Mass of proton 1.67 x 10 kg. 5. A uniform electric field of magnitude 430 N/C, incident perpendicularly at the back of a wedge-shaped object, emerges on the other side of it as illustrated in Figure 5. Using the dimensions of the wedge shown in the Figure, determine the following: E- a. The flux through the slanted front side of b. The flux through the back side of the c. The flux through each of the two triangular d. The flux through the bottom side of the e· The total flux through the wedge the wedge wedge sides of the wedge wedge 0 m 14.0 m 8.0 m Figure 5

Explanation / Answer

4.Electric force is given by:

F = q*E

q = Charge on proton

E = electric field

So,

F = (1.6*10^-19 C)*(5.75*10^-12 N/C)

F = 9.2*10^-31 N

4B.

Using Newton's 2nd law:

F = m*a

So acceleration will be given by

a = F/m

m = mass of proton

a = 9.2*10^-31 N/(1.67*10^-27 kg)

a = 5.51*10^-4 m/sec^2

4C.

Using equation

V = U + a*t

U = initial Velocity = 0 m/sec

t = 6.00 sec

a = 5.51*10^-4 m/sec^2

So,

V = final velocity = ?

V = 0 + 5.51*10^-4*6.00

V = 3.31*10^-3 m/sec

4D.

Distance traveled by proton will be given by:

S = U*t + 0.5*a*t^2

S = 0*6 + 0.5*5.51*10^-4*6^2

S = 9.92*10^-3 m

4E.

Kinetic energy is given by:

KE = 0.5*m*V^2

KE = 0.5*1.67*10^-27 kg*(3.31*10^-3 m/sec)^2

KE = 9.15*10^-33 J

KE = 9.15*10^-33/(1.6*10^-19) eV

KE = 9.15*10^-33 J = 5.72*10^-14 eV

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