PHYS 255A Quiz 4 practice Session Name A ball B1 of mass 2 moves at speed of 2m/
ID: 1782565 • Letter: P
Question
PHYS 255A Quiz 4 practice Session Name A ball B1 of mass 2 moves at speed of 2m/s. A ball B2cfnn ass 3kg moves at speed oame They tulide at an angle of 30. A) Find the total momentum before the collision in x and y direction. (Hint: compute B1's and B2's 1. momentum in x and y. Then sum up them. Be careful that only B2 has speed in Y mis2k 45 2m/s 30 4m/s After collisson, they go separately at an angle of 45. Find the speed of Bl. (Hint: make an equation for the momentum in y direction by using conservation law of momentum B) C) Find the speed of B2 (Hint: make an equation for the momentum in x direction)Explanation / Answer
A)
m1 = 2 kg
v1 = 2 m/s
m2 = 3 kg
v2 = 4 m/s
B1’s momentum, x-component ====> 4 kgm/s
y-component ====> 0 kgm/s
B2’s momentum, x-component ====> -3*4*cos30 = -10.4 kgm/s
y-component ====> -3*4*sin30 = -6 kgm/s
Total momentum in x-direction ====> 4 – 10.4 = -6.4 kgm/s (In -x-direction)
Total momentum in y-direction ====> -6 kgm/s (In -y-direction)
B) After collision,
Total momentum in y-direction ====> 2*v*sin45
Now momentum conservation in y-direction, then
6 = 2*v*sin45
v = 6/2*sin45 = 4.24 m/s
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