Lab 3: Acceleration Due to GPavit ve - vi Lab 3: Acceleration Due to Gravity To

Question

Lab 3: Acceleration Due to GPavit ve - vi Lab 3: Acceleration Due to Gravity To study and apply the equations for one-dimensional motion with constanst acceleration Objective: Materials: 4Tennis Balls Stopwatch (record all time in seconds) Measuring Tape (measure all distances in meters) . The skywalk at Lone Star College Montgomery is 12 meters high. From this skywalk, hold a ball and release it underhand, one meter above the skywalk, so that the ball travels straight upwards. The ball travels in a one-dimensional path and hits the ground below 3.0 seconds later. Assume that during the flight, gravity is the only force acting on the ball. Pre-Lab: I. What is the value of the ball's acceleration in the vertical direction? 2. Solve for the initial vertical velocity of the ball just after it leaves your -a because You thronw the ball hand). nitial veloci+

Explanation / Answer

Time taken by the ball to reach the ground is t = 3 sec

acceleration due to gravity a = - 9.8 m/s2

displacement from the initial position ( 1 m above the skywalk ) to the final position ( ground ) is

d = - 13 m

displacement equation

d = Vo*t + 1/2at2

-13 = Vo(3) + 1/2(-9.8)(32)

-13 = 3Vo - 44.1

3Vo = 31.1

Vo = 10.37 m/s

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