1 of7> verage Velocity from a Position vs. Time Graph calculate average velocity

Question

1 of7> verage Velocity from a Position vs. Time Graph calculate average velocity (Figure 1) In this problem you will dehermine the average velocity of a moving object from the graph of its position z(t) as a function of time t. A traveling object might move at difflerent speeds and in ifferent directions during an nterval of time, but If we ask at what constant velocity the object would have to travel to achieve the same Part A Consulting the Answer to the nearest integer graph shown in the figure, find the object's average velocity over the time interval from O to 1 second View Available Hints osplacement over the given tirre interval, hat is what we call the objects average velocity. We will use the 1,fal to indicabe average velocity over the rotation " ime inteeval from ti to 12.For iestance,e1,3 is the everage velocity over the time intervasi from t-1to t-3 m/s Figure 1of1 Submit Previous Answers X Incorrect; Try Again; 8 attempts remaining Part 8 answer in meters per second to the nearest integer View Available Hint(s Time (seconds)

Explanation / Answer

A)from graph, the object is stationary between 0 to 1, so the average velocity is zero

Vave(0,1) = 0 m/s

B)dx = (60 - 20) = 40 ; t = 3 - 1 = 2 s

Vave = 40/2 = 20 m/s

Hence, Vave(1,3) = 20 m/s

C)dx = 60 - 20 = 40 ; t = 3 - 0 = 3

Vave = 40/3 = 13.33 m/s

Hence, Vave(0,3) = 13.33 m/s

D)dx = -40 m/s ; t = 3

Vave = -13.33 m/s

Hence, Vave(3,6) = -13.33 m/s

E)Vave(0,6) = 0 m/s

Since there us ni change in position as its back to origin.

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