1 of 2 CS 250 Computer Networks Fundamentals Fall 2016 Homework 3 A network admi

Question

1 of 2 CS 250 Computer Networks Fundamentals Fall 2016 Homework 3 A network administrator is trying to redesign the network by dividing it into smalier subnets. The following are the requirements for these subnets: Subnet 1: 50 PCs Subnet 2: 60 PCs Subnet 3: 30 PCs Subnet 4: 30 PCs Subnet 5: 30 PCs Subnet 6: 10 PCs Subnet 7: 10 PCs Using 192.168.43.0/24 to create these subnets, complete the following: The network address of Subnet lis: The first usable address in Subnet lis: The last usable address in in Subnet 1 is: The broadcast address of in Subnet 1 is: The network address of Subnet 2 is: The first usable address in Subnet 2 is: The last usable address in in Subnet 2 is: The broadcast address of in Subnet 2 is: The network address of Subnet 3 is: The first usable address in Subnet 3 is: The last usable address in in Subnet 3 is: The broadcast address of in Subnet 3 is:

Explanation / Answer

a)

The network address will be the subnet id 192.168.43.0

first usable address will be 192.168.43.1

Last address will be 192.168.43.50 (for pc number 50)

Broadcast address will be 192.168.43.63

b)

The network address will be the subnet id 192.168.43.64

first usable address will be 192.168.43.65

Last address will be 192.168.43.125 (for pc number 60)

Broadcast address will be 192.168.43.127

c)

The network address will be the subnet id 192.168.43.128

first usable address will be 192.168.43.129

Last address will be 192.168.43.158 (for pc number 30)

Broadcast address will be 192.168.43.159

d)

The network address will be the subnet id 192.168.43.160

first usable address will be 192.168.43.161

Last address will be 192.168.43.190 (for pc number 30)

Broadcast address will be 192.168.43.191

e)

The network address will be the subnet id 192.168.43.192

first usable address will be 192.168.43.193

Last address will be 192.168.43.222 (for pc number 30)

Broadcast address will be 192.168.43.223

f)

The network address will be the subnet id 192.168.43.224

first usable address will be 192.168.43.225

Last address will be 192.168.43.234 (for pc number 10)

Broadcast address will be 192.168.43.239

g)

The network address will be the subnet id 192.168.43.240

first usable address will be 192.168.43.241

Last address will be 192.168.43.250 (for pc number 10)

Broadcast address will be 192.168.43.255

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