A 1065 kg automobile is pulled by s honizontal tow line with a net force of 816

Question

A 1065 kg automobile is pulled by s honizontal tow line with a net force of 816 N. What is the acceleration of the auto? (Neglect friction.) x m/s Suit Anwer Save Progres Practice Another Vernsion -142 points riPS13 3E.014 The separation distance between two 1.0 kg masses is changed. How is the mutual gravitational force affected in each case? (Assume Fa represents the new force and Fi represents the original force) My (a) The separation distance is two-thirds the original distance. (b) The separation distance is 6 times the original distance

Explanation / Answer

2)

let the acceleration is a

Using second law of motion

816 = 1065 * a

a = 0.77 m/s^2

the acceleration of the auto is 0.77 m/s^2

3)

as the mutual force is given as

F = G * m^2/d^2

for the distance is two third distance

F2/F1 = 1/(2/3)^2

F2/F1 = 9/4

b)

for the distance is 6 times

F2/F1 = 1/(6)^2

F2/F1 = 1/36

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