TENTATIVE CLASSTA Mercer Louney community Lonege Varlables Algebra is used to so
ID: 1877070 • Letter: T
Question
TENTATIVE CLASSTA Mercer Louney community Lonege Varlables Algebra is used to solve most of the problems in this course. However seem different than the typical problems in an algebra class. in mat for unknown varlables; while a, b, and c are usually used for constants the application to physics may mathermatics, x, y, and z are usually used in physics, is indicated using (delta), for All letters can be used as unknowns or constants. Displacement example dx or dyy A letter with a subscript is used to represent a specific property. For velocity of an object at time t-O. Symbols that represent physical properties are case-sensitive. 1. 2. M and m are different properties. Solve the following equations. Notice the way symbols are used to represent different properties Solve for x2-98)-1.00 10) x 96o0 There are four variables in the following equation. Use wo-o, g-9.8, --1.00 . 10 Solve for x: x2-102+2gy There are four variables in the following equation. Use vo = 0, Solve for v: o+2gdy -9.8, by =-1.00 * 103 os) Quadratic Equation Solve for x: 1.00 102-4.90 x Solve for t: -1.00 1024.90tExplanation / Answer
1) Given equation, x^2 = 2(-9.8)(-1.00×10^3)
=> x^2 = 19.6×10^3 = 19600
Taking square root on both sides, we have,
x = 140
2) Given equation, x^2 = (vo)^2 + 2gy
Putting the values of vo, g and y as given, we get,
x^2 = 0^2 + 2(-9.8)(-1.00×10^3) = 19600
Taking square root on both sides of above equation,
x = 140
3) Quadratic Equation
Given equation is, -1.00×10^2 = -4.90 x^2
=> x^2 = -1.00×10^2/-4.90 = 20.40816
Taking square root on both sides of above equation,
x = 4.52
4) Given equation is, -1.00×10^2 = -4.90 t^2
=> t^2 = -1.00×10^2/-4.90 = 20.40816
Taking square root on both sides of above equation,
t = 4.52
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