013 (part 1 of 2) 10.0 points Given a mean free path of 0.4 nm and a mearn speed
ID: 1876249 • Letter: 0
Question
013 (part 1 of 2) 10.0 points Given a mean free path of 0.4 nm and a mearn speed of 1.17 x 105 m/s for the electrons in copper at a temperature of 300 K, caleulate the resistivity of copper. The free-electron number density of copper is 8.47 x 102% m3 the electron mass is 9.109 × 10-31 kg and the fundamental charge is 1.602 × 10-19 C Answer in units of ·m. 014 (part 2 of 2) 10.0 points The classical model suggests that the mean free path is temperature independent and that- tai depends on temperatuire From this model find the resistivity at 100 K. Boltzmann's constant is 1.3810 23 JK 1 Answer in units of . 111. 015 10.0 points How do the length. diameter and temperatureExplanation / Answer
13)
Resistivity (rho) in terms of mean free path (d) and mean speed (v) is written as: rho = (m*v) / ( N*e2*d)
N is the electron density ; e is charge on 1 electron and m is mass of electron.
On substituting the values, we get rho = 1.2257*10-7 ohm meter or 0.12257 mu ohm meter.
Accordin to chegg guidelines, we are not supposed to solve multiple question in one go.Please post the other question as a separate one.Thanks
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.