01. Questions (a) to G) are \"drill\" problems meant to help you familiarize you
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01. Questions (a) to G) are "drill" problems meant to help you familiarize yourself with the thermodynamic tables. All these questions involve either reading off values or interpolating between given values to determine the unknown parameters. For each question: First deduce in which region of the p-o and T- u diagrams does the system lie (liquid? liquid-vapor? vapor?), explaining briefly how you arrived at your conclusion. Indicate in words the state of the system (superheated vapor', etc.). asked for in the question. isotherm. Label the f and 'g' points. State the appropriate table to use and using this table, determine the missing quantities Draw an approximate (not to scale) sketch showing the state of the system in both the p-v and T-u diagrams. Your sketch should indicate the vapor dome, the relevant isobar and Write down the specific volume at the saturated liquid (f) and saturated vapor states Note: If you think the given data is insufficient to determine the unknown quantity, explain in a sentence or two why and state what further information you would need to complete the calculation. (a) p 7.5 MPa, T 140 C, u? (b) p 6 MPa, v 0.045 m'/kg, T-? [Hint: For a given pressure, how do you find out whether the given value of v lies inside the vapor dome? Think about where the isobar intersects the vapor dome.] (c) p-3.0 bar, T 133.6 C, u- (d) T-60 C, 1.0172 x 103 m/kg, p-? (e) p-22.09 MPa, u 3.155 x 103 m/kg, T-? (f) p 10 MPa, u=500 kJ/kg, T = ? (g) T-200 C, p. 15.54 bar, x-04,-? (h) p-3 bar, u-2860 kJ/kg, T-? (i) T-120 C for a saturated liquid-vapor mixture, x-1, u-? G) p-16 MPa, u-3000 kJ/kg, u-?Explanation / Answer
a) P= 7.5 MPa T= 140 0C v= 1.075 x 103 m3/kg. It is compressed liquid state
b)P=6 MPa v=0.45 m3/kg T= 3800C Here A(Vl= .04331 Tl= 360 0C) B( Vg= 0.04739 and Tg= 4000C It is super-heated water vapor state
C)P=3.0 bar T=133.60C Vl= 1.0732 x 10-3 m3/kg and Vg= 0.6058 x 10-3 m3/kg It is saturated liquid vapor state
d) T = 60 0C v= 1.0172 x 10-3 m3/kg P=.2 bar. It is saturated liquid vapor state
e) P= 22.09 MPa v= 3.155 x 10-3 m3/kg T= 374.10C It is saturated liquid vapor state
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