dr Osteopathie l ERROR 404 1. COMOfficec/X Womens-Ke K Aldehyde Nor X. Universit
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dr Osteopathie l ERROR 404 1. COMOfficec/X Womens-Ke K Aldehyde Nor X. University fix e Determine Thx s 80s themed- man .> C | www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=5225494 Apps Bookmarks bedroom surrounds.- ti 1U Other bookmark Sapling Learning Jump to... Nicole Levy macmilan learning Due Date Mapoc Sapling Learning Allowed with 10% of the points possible deducted per day until 03/03/2018 11:59 PM Late submissions: Determine the direction of the force (if any) that will act on the charge in each of the following situations. A positive charge within an electric field that points upward. Points Possible: 100 Grade Category: Homework Assignments A negative charge within an electric feld that points to the left. to the lett Module 19. From a charge in a magnetic field to the force between parallel wires. e moving into the screen in a A positive magnetic field that points to the right. MyPolicy2 Policies: You can check your answers. You can view solutions after the due date You have ten attempts per question. There is no penalty for incorrect answers. For multiple-choice questions, the penalty depends on the number of choices available. A negative charge moving magnetic field that points out of the screen. to the lef 10 A positive charge moving to the left in an electric field that points into the screen. out of the screen 12 3 A negative charge moving upward in a magnetic field that points upward. zero force eTextbook 13 1 14 out of tha sareenzoro forcoupward dawnward into the scroon) to the letta the right Help with This Topic 15 2 Previcus Check AnrNeExt 824 PM O Type here to search 2/24/2018Explanation / Answer
A) ;For a positive charge, the direction of the force due to electric field is in the direction of the electric field. So as electric field points upwards, so will be the force. Thus force will be upwards.
B) :for a negative charge, the electric field applies force in the direction opposite to the electric field. So here force will be towards right.
C) :here force =q* vxB where v=velocity and B=magnetic field.
As v=inside the screen, say along -K and B is along i we have
F=qvB(-k x i) = -j i.e along Negative y direction or downwards.
D) :using conventions as used in part C we have
V=j and B= along k
So F= (-q) vj x Bk
F=qvb(-j x k)
F=along - i or along Negative x direction,or towards left.
E);electric force doesn't depend on the direction of velocity as magnetic force does. Since here charge is positive, so electric force will be along the electric field. I.e inside the screen.
F) ;magnetic force= q vxB =qvBsinc where c=angle between velocity and magnetic field. As here c=0 we have F=0.
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