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Question

) d http://eduger.wl., p-a c ||Ng WileyPLUS d WileyPLUS WileyPLUS: MyWileyPLUs I Hep I Contact Us Cutnell, Physics, 10e GENERAL PHYSICS (PHYS 20 Assignment Gradebook ORION Downloadable eTextbook Practice signment FULL SCREEN PRINTER VERSION BACK Chapter 06, Problem 44 GO A small lead ball, attached to a 1.55-m rope, is being whirled in a dirde that lies in the vertical plane. The ball is whirled at a constant rate of three revolutions per second and is released on the upward part of the circular motion when it is 1.9 m above the ground. The ball travels straight upward. In the absence of air resistance, to what maximum height above the ground does the ball rise? the tolerance is +/-296 GO TUTORIAL LINK TO TEX Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER MapleNet Vers on 4.2

Explanation / Answer

Solution :-

v= 3*(2*pi*(1.55 m)) / 1 s
= 29.22 m/s
by conservation of energy, we have:
(1/2)m*v^2 + mgh = 0+mgH
(1/2)v^2 + gh = gH
H = ((1/2)v^2 + gh)/g = v^2/(2g) + h
= (29.22 m/s)^2/(2*(9.8m/s^2)) + 1.9m
= 45.417m

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