Some physical properties of water are shown below. 6.19 kJ of heat are added to

Question

Some physical properties of water are shown below.

6.19 kJ of heat are added to 25.8 g of ice at -4.8°C.

(a) What will be the final temperature of the system? and what mass will be in each phase after the heating?
___  °C
(b) What mass will be in each phase after the heating? Enter zero for any physical state that is not present.
___ g (solid)
___g (liquid)
___ g (gas)

melting point 0.0°C boiling point 100.0°C specific heat solid 2.05 J/g·°C specfic heat liquid 4.184 J/g·°C specific heat gas 2.02 J/g·°C H° fusion 6.02 kJ/mol H° vaporization 40.7 kJ/mol

Explanation / Answer

heat required to take the ice from -4.8 C to 0 C,
Q1 = 25.8*2.05*(0 - (-4.8))

= 254 J

Heat required to melt the ice,
Q2 = 25.8*333

= 8591 J

But heat added is 6.9 kJ, so total Ice does not melt.

let m is the mass of Ice that melts.

(6.19*10^3 - 254) = m*333

==> m = (6.19*10^3 - 254)/333

= 17.8 grams

a) 0 degrees celsius

b) solid = 25.8 - 17.8

= 8 grams

liquid = 17.8 grams

gas = 0 grams

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