isterm) Free a (kJ/mol) Phosphoenolpyruvate 1,3-bisphosphoglycerate -61.9 CH, -5
ID: 187478 • Letter: I
Question
isterm) Free a (kJ/mol) Phosphoenolpyruvate 1,3-bisphosphoglycerate -61.9 CH, -50 Phosphocreatine ADP ( AMP + P') ATP ( ADP + Pi) ATP ( AMP + PP) AMP (adenosine + P) 49.3 -43.0 -32.8 -30.5 -45.6 -14.2 -19.2 20.9 -15.9 -13.8 -0-P 1,3-Bisphosphoglycerate -40 Adenine RibPPP -30 ATP Glucose 3-phosphate Fructose 6-phosphate Glucose 6-phosphate Glycerol 3-phosphate Acetyl-CoA Glucose& Glycerol- -10 -9.2 -31.4 Figure 13-19 The figure shows standard free energies (AG°) of hydrolysis of some biologically important compounds Acetyl-CoA ligase (or acetyl-CoA synthetase) catalyzes the formation of acetyl-CoA from acetate and CoA. Acetate + CoA Acetyl-CoA + H2O In this process, two molecules are joined to become an energy-rich molecule. You can predict that the reaction as written will be unfavorable and needs to be coupled with an energy-yielding process. You can also see that there are two plausible ways to achieve this: Acetate+ CoA Acetate + CoA + ATP Acetyl-CoA + AMP + PPi + ATP Acetyl-CoA + ADP + Pi Reaction I: Reaction 2: Referring to the table above, which reaction is more likely to be used for the formation of acetyl- CoA in cells? Explain. Disregard mass-action effects.Explanation / Answer
Reactions with a negative G release energy, which means that they can proceed without an energy input (are spontaneous) wheras reactions with a positive G need an input of energy for reaction to take place (are non-spontaneous).
A negative G means that the reactants, or initial state, have more free energy than the products, or final state. Therefore, the reaction 2 having more negative free energy will be likely to be used in the formation of Acetyl CoA in the cells.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.