2 The two wires shown in the figure carry currents of I5.87 A in opposite direct

Question

2 The two wires shown in the figure carry currents of I5.87 A in opposite directions and are separated by a distance of do 8.13 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer. -5.78x10-5 T You are correct. Previous Tries Calculate the net magnetic field at point P1 - that is 8.62 cm to the right of the wire on the right. 6.61x10-6 T You are correct. Previous Tries Calculate the net magnetic field at point P2 - that is 21.1 cm to the left of the wire on the left. 5208 T Submit Answer Incorrect. Tries 1/20 Previous Tries

Explanation / Answer

1) magnetic field at a point midpoint between the wires

Bnet = - Uo*I/(2*pi*do/2)  - Uo*I/(2*pi*do/2) =   -2* Uo*I/(2*pi*do/2) = -2*Uo*I/(pi*do)

=> Bnet = -2*4*pi*10^-7*5.87/(pi*0.0813) = - 5.776*10^-5 T

2) net magnetic field at point p1

Bnet = Uo*I/(2*pi*d1) - Uo*I/(2*pi*(d1+do))  

=> Bnet = [Uo*I/(2*pi)]*[1/d1 - 1/(d1+do) ] =  2*10^-7*5.87*[ 1/0.0862 - 1/0.1675] = 6.608*10^-6 T

3) net magnetic field at point p2

Bnet = Uo*I/(2*pi*d2) - Uo*I/(2*pi*(d2+do))  

=> Bnet = [Uo*I/(2*pi)]*[1/d2 - 1/(d2+do) ] = 2*10^-7*5.87*[ 1/0.211 - 1/0.2923] = 1.53*10^-6 T

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