HW 06 Problem1 A wire is placed between the poles of a strong magnet so that 4.0
ID: 1873833 • Letter: H
Question
HW 06 Problem1 A wire is placed between the poles of a strong magnet so that 4.00 cm of it are perpendicular to the magnetic field. When a 30.0 A currents passes through the wire, the wire in the field experiences a 2.16-N force. What is the average field strength? Problem 2 A wire that carries an 8.00-A current is partially placed in a magnetic field of 1.20 T (a) If the portion of wire inside the magnetic field is 5.0 cm long and it experiences a force of 2.40 N, whot is the angle between the wire and the field? (b) What is the force on the wire if it is rotated to make an angle of 90° with the field? Problem 3 The force on the rectangular loop of wire in the magnetic field in the figure below can be used to measure field strength. The field is uniform, and the plane of the loop is perpendicular to the field. (a) What is the direction of the magnetic force on the loop? Justify the claim that the forces on the sides of the loop are equal and opposite, independent of how much of the loop is in the field and do not affect the net force on the loop. (b) If a current of 5.00 A is used, what is the force per tesla on the 20.0-cm- wide loop?Explanation / Answer
Only one question can be posted as per chegg guidelines
1.
Magnetic force is given by
F=BILsin(o)
2.16=B*30*0.04*sin90
B=1.8 T
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.