5. -2 points SerCP11 18.P011 My Notes Ask Your Consider the arcuit shown in the

Question

5. -2 points SerCP11 18.P011 My Notes Ask Your Consider the arcuit shown in the figure below. (Assume R1 = 16.0 and R2 = 3.00 .) 250 V Ry Ri 20.0 (a) Find the potential difference between po nts a and b. (b) Find the current in the 20.0-12 resistor Need Help? Read It -44 points SArCP11 18.P018 My Notes Ack Your consider the following figure. Note: The currents are not necessarily in the direction Shown. (Assume R1-26.0 ,R2-8.5 , and V-27 V.) 21 12 (a) Find the current in each resistor of the figure above by using the rules for resistors in series and paralel. 8.5 26 052 24 rough the battey, the 8.5 esi tor, and the 24.0 ess ; and the third using the io p rule through the 26 and 24.0 b write three independent equations or the three cu ents using K ch s laws one with the de ule; a second using the loop rule resistors, solve to check the answers found in part (a). (Submit a file with a maximum size of 1 MB.) Choose File No fle chosen This answer has not been graded yet. Need Help? Resd 3 points SerCP 0 18 P017 My Notes Ask Your

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5.

a)

R2 and 20 ohms are in series

r1=20+3=23 ohms

R1 ,R2 and r1 are in parallel

1/r2=1/16 +1/3 +1/23

r2=2.276 ohms

R1 and r2 are in series ,so equivalent resistance

Req =16+2.276=18.276 ohms

Total Current

I=V/Req =25/18.276=1.368 A

Potential difference between a and b is

Vab =1.368*2.276

Vab =3.114 volts

b)

Voltage across 20 ohms is

V20=3.114*(20/20+3)=2.707 Volts

Current through 20 ohms is

I20=2.707/20=0.1354 A

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