A 76 cm-long, 0.8 mm-diameter copper wire carries a current of 36.0 A to the sou

Question

A 76 cm-long, 0.8 mm-diameter copper wire carries a current of 36.0 A to the south. Suppose we create a magnetic field that produces an upward force on the wire exactly equal in magnitude to the wires weight, causing the wire to “levitate.” What are the magnetic field in G(gauss)? Use the convention: west = positive, east = negative for the direction. A 76 cm-long, 0.8 mm-diameter copper wire carries a current of 36.0 A to the south. Suppose we create a magnetic field that produces an upward force on the wire exactly equal in magnitude to the wires weight, causing the wire to “levitate.” What are the magnetic field in G(gauss)? Use the convention: west = positive, east = negative for the direction. A 76 cm-long, 0.8 mm-diameter copper wire carries a current of 36.0 A to the south. Suppose we create a magnetic field that produces an upward force on the wire exactly equal in magnitude to the wires weight, causing the wire to “levitate.” What are the magnetic field in G(gauss)? Use the convention: west = positive, east = negative for the direction.

Explanation / Answer

density of copper wire is 8960 kg/m^3

Volume of copper wire is V = pi*r^2*l = 3.142*(0.4*10^-3)^2*0.76 = 3.82*10^-7 m^3

mass of the copper wire is m = density * Volume = 8960*3.82*10^-7 = 0.003422 Kg

Given that Electric force = weight

i*l*B = m*g

36*0.76*B = 0.003422*9.81

B = 0.00122 T

B = 0.00122*10^4 G

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