My Note A donkey is harnessed to a sled having a mass of 241 kg, including suppl

Question

My Note A donkey is harnessed to a sled having a mass of 241 kg, including supplies. The donkey must exert a force exceeding 1190 N at an angle of 32.30 (above the horizontal) in order to get the sled moving. Treat the sled as a point particle. HINT ) Calculate the normal force (in N) on the sled when the magnitude of the applied force is 1190 N. (Enter the magnitude.) o) Find the coefficient of static friction between the sled and the ground beneath it. (e) Find the static friction force (in N) when the donkey is exerting a force of 5.95-10 N on the sled at the same angle. (Enter the magnitude.)

Explanation / Answer

(A) in vertical,

Fnet = N + Fsin32.3 - m g = 0

N = (241 x 9.8) - (1190 sin32.3)

N = 1726 N ......Ans

(B) in horizontal,

Fnet = F cos32.3 - fs = 0

and fs =us N

1190 cos32.3 - us (1726) = 0

us = 0.583  

(C) in horizontal,

Fnet = F cos32.3 - f = 0

f = 595 cos32.3 = 503 N

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