A -50 nC charged particle is in a uniform electric field E = (30 V/m , east). An
ID: 1873305 • Letter: A
Question
A -50 nC charged particle is in a uniform electric field E = (30 V/m , east). An external force moves the particle 2.0 m north, then 6.0 m east, then 7.0 m south, and finally 5.0 m west. The particle begins and ends its motion with zero velocity.
Part A
How much work is done on it by the external force?
A -50 nC charged particle is in a uniform electric field E = (30 V/m , east). An external force moves the particle 2.0 m north, then 6.0 m east, then 7.0 m south, and finally 5.0 m west. The particle begins and ends its motion with zero velocity.
Part A
How much work is done on it by the external force?
Explanation / Answer
Given,
q = -50 nC ; F = 30 V/m
a)We know that the work done by the electric force is:
W = q E d
W = 50 x 10^-9 x 30 x (6 - 5) = 1.5 x 10^-6 J
Hence, W = 1.5 x 10^-6 J
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