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Secure https//session.masteringphysics.com/myct/itemView?offset-next&assignmentProblemiD-91973310; Chapter 19 HW tem 12 Express your answers in terms of the variables V and C separated by commas. Constants In (Figure 1), suppose G = C2 = C3 = C-C. Submit Previous Answers Request Answer Incorrect; Try Again: 5 attempts remaining Term 1: The correct answer involves the variable C, which was not part of your answer Term 2: The correct answer involves the variable C, which was not part of your answer Term 3: The correct answer involves the variable C, which was not part of your answer Term 4: The correct answer involves the variable C, which was not part of your answer Figure 1 of 1 Part C Determine the potential difference across each capacitor Express your answers in terms of V separated by commas.

Explanation / Answer

from fig, C1 and C2 are in series ,so its capacitance will be

1/ Cs = 1/ C1 + 1/ C2

= 1/ C + 1/C

= 2/ C

Cs ( capacitance of C1 and C2) = C / 2

now it will be in parallel with C3 ,so equivalent capacitance will be:

Ceq = (C/2) + c3

= ( C/ 2) + C

= 1.5 C

now Ceq will be in series with C4 ,so total capacitance between an and b

= 1 / 1.5 C + 1/ C

= 0.6 C

charge  of C4, Q4 = (V of C4) * C4 ( Q = C*V)

Q4 = 0.6V*C

charge of C3, Q3 = (V of C3) * C3

Q3 = 0.4V * C

charge of C2, Q2 = (V of C2) * C2

Q2 = 0.2V * C

charge of C1,Q1 = (V of C1) * C1

Q1 = 0.2V * C

b)

V ( potential difference) = (V of C4) + (V of Ceq)

where Ceq = (C1 series C2) || C3) = 1.5 C

So the voltages of C4 = C and Ceq= (1.5C) are

V of C4 = (Ceq / (C4 + Ceq)) * V

V of C4 = (1.5C / (C + 1.5C)) * V

V of C4 = (1.5C / 2.5C) * V

V of C4 = 0.6V

V of Ceq = (C4 / (C4 + Ceq)) * V

V of Ceq = (C / (C + 1.5C)) * V

V of Ceq = (C / 2.5C) * V

V of Ceq = 0.4V

V of C3 = V of Ceq [ because they are in parallel ]

= 0.4 V

since C1 = C2,and they are in series and in parallel with C3 so they are each 1/2 of V of C3

V of C2 = 0.2V

V of C1 = 0.2V

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